What is the probability of rolling a 1, 3, or 9 on a six-sided die?

To determine the probability of rolling a 1, 3, or 9 on a six-sided die, it's essential to consider the possible outcomes when rolling the die. A standard six-sided die has the numbers 1 through 6 on its faces, so rolling a 9 is impossible.

The total number of possible outcomes when rolling the die is 6 (the numbers 1, 2, 3, 4, 5, and 6). Of the numbers specified in the question, only the numbers 1 and 3 are present on the die. Therefore, there are 2 favorable outcomes (rolling a 1 or rolling a 3) out of the total of 6 possible outcomes. However, since one of the chosen numbers, 9, does not exist on the die at all, the overall probability of rolling a 1, 3, or 9 is based solely on the fact that 9 cannot occur, resulting in no successful outcomes.

Thus, the probability is calculated as the number of favorable outcomes (which are the successful rolls of 1 or 3) divided by the total outcomes (6). When considering the inclusion of number 9, it effectively results in zero successful outcomes